Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 14 - A Preview of Calculus: The Limit, Derivative, and Integral of a Function - Chapter Review - Review Exercises - Page 906: 13


not continuous

Work Step by Step

We know that the fraction $\frac{x^2-4}{x+2}$ is undefined if its denominator is $0$. $x+2\ne0$, hence $x\ne2$, hence it is continuous everywhere, apart from where it is undefined, therefore it is not continuous at $-2$.
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