## Precalculus (10th Edition)

a) $0.68$ b)$0.58$ c)$0.32$
We know that $P(A\cup B)=P(A)+P(B)-P(A\cap B).$ T:tune up, B:break a) Hence here $P(T\cup B)=P(T)+P(B)-P(T\cap B)=0.6+0.1-0.02=0.68.$ b) We know that $P(T\cap \overline{B})=P(T)-P(T\cap B)=0.6-0.02=0.58.$ c) We know that $P(\overline{T\cup B})=1-P(T\cup B)=1-0.68=0.32.$