Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 13 - Counting and Probability - Chapter Review - Review Exercises - Page 869: 25

Answer

$0.2,0.26$

Work Step by Step

We know that probability$=\frac{\text{number of favourable outcomes}}{\text{number of all outcomes}}.$ There are $100$ integers from $1$ to $100$ inclusive. Out of these $5,10,25,20,25,30,35,40,45,50,55,60,65,70,75,80,85,90,95,100$ are divisible by $5$ ($20$ numbers). Thus the probability here: $\frac{20}{100}=0.2$. Out of the $100$ integers $2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,53,59,61,67,71,73,79,83,89,97$ are primes $5$ ($26$ numbers). Thus the probability here: $\frac{26}{100}=0.26$.
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