Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 13 - Counting and Probability - Chapter Review - Review Exercises - Page 869: 24



Work Step by Step

We know that $\text{probability}=\frac{\text{number of favourable outcomes}}{\text{number of all outcomes}}=\frac{n(E)}{n(S)}.$ Hence here because we have $4$ $\$1$ bills, $n(E)=4$, in total we have $n(S)=4+3+2=9$ bills, therefore $\text{probability}=\frac{4}{9}.$
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