Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 13 - Counting and Probability - Chapter Review - Chapter Test - Page 869: 5

Answer

$5040.$

Work Step by Step

We know that $n!=n\cdot(n-1)\cdot...\cdot2\cdot1.$ Hence here $7!=7\cdot6\cdot5\cdot4\cdot3\cdot2\cdot1=5040.$
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