Answer
a) $0.95$
b)$0.3$
Work Step by Step
We know that $P(A\cup B)=P(A)+P(B)-P(A\cap B)$ and that $P(\overline{A})=1-P(A)$ U:admitted to USC, F:admitted to FSU
a) Hence here $P(U\cup F)=P(U)+P(F)-P(U\cap F)=0.6+0.7-0.35=0.95.$
b) $P(\overline{F})=1-P(F)=1-0.7=0.3$
