Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 13 - Counting and Probability - Chapter Review - Chapter Test - Page 869: 15

Answer

$\frac{1}{30240}$.

Work Step by Step

We know that $\text{probability}=\frac{\text{number of favourable outcomes}}{\text{number of all outcomes}}=\frac{n(E)}{n(S)}.$ We know that $\text{number of favourable outcomes}=1$, whilst $\text{number of all outcomes}=P(10,5)=10\cdot9\cdot8\cdot7\cdot6=30240.$ Hence probability=$\frac{1}{30240}$.
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