Answer
$(0,-4),(0,4),(-2,0),(2,0)$
Work Step by Step
We are given the equation:
$y^2=16-4x^2$
Determine the intercepts:
$y=0\Rightarrow 16-4x^2=0\Rightarrow x^2=4\Rightarrow x=\pm 2$
$x=0\Rightarrow y^2=16-4(0^2)\Rightarrow y^2=16\Rightarrow y=\pm 4$
The intercepts are:
$(0,-4),(0,4),(-2,0),(2,0)$
