## Precalculus (10th Edition)

$\sqrt{13}$
The distance $d$ from $P_1(x_1,y_1)$ to $P_2(x_2,y_2)$ is given by the formula $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ Hence, using the formula above gives $d=\sqrt{(4-2)^2+[-2-(-5)]^2}\\ d=\sqrt{2^2+3^2}\\ d=\sqrt{4+9}\\ d=\sqrt{13}$