Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 10 - Analytic Geometry - 10.3 The Ellipse - 10.3 Assess Your Understanding - Page 656: 2



Work Step by Step

We complete the square: $x^2-3x=x^2-2\cdot\dfrac{3}{2}x=x^2-2\cdot\dfrac{3}{2}x+\left(\dfrac{3}{2}\right)^2-\left(\dfrac{3}{2}\right)^2$ $=\left(x-\dfrac{3}{2}\right)^2-\dfrac{9}{4}$ To complete the square $x^2-3x$, add $\dfrac{9}{4}$.
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