Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix B - Graphing Utilities - B.1 The Viewing Rectangle - B.1 Exercises - Page B2: 8

Answer

$X_{max}=9,X_{min}=-9,Y_{max}=4,Y_{min}=-12,X_{scl}=3,Y_{scl}=4.$

Work Step by Step

As we can see on the figure: $X_{max}=9,X_{min}=-9,Y_{max}=4,Y_{min}=-12.$ There are $6$ sections on the "x-axis", hence $X_{scl}=\frac{X_{max}-X_{min}}{6}=\frac{9-(-9)}{6}=3.$ There are $4$ sections on the "y-axis", hence $Y_{scl}=\frac{Y_{max}-Y_{min}}{4}=\frac{4-(-12)}{4}=4.$ Thus $X_{max}=9,X_{min}=-9,Y_{max}=4,Y_{min}=-12,X_{scl}=3,Y_{scl}=4.$
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