## Precalculus (10th Edition)

$X_{max}=6,X_{min}=-6,Y_{max}=3,Y_{min}=-1,X_{scl}=2,Y_{scl}=1.$
As we can see on the figure: $X_{max}=6,X_{min}=-6,Y_{max}=3,Y_{min}=-1.$ There are $6$ sections on the "x-axis", hence $X_{scl}=\frac{X_{max}-X_{min}}{6}=\frac{6-(-6)}{6}=2.$ There are $4$ sections on the "y-axis", hence $Y_{scl}=\frac{Y_{max}-Y_{min}}{4}=\frac{3-(-1)}{4}=1.$ Thus $X_{max}=6,X_{min}=-6,Y_{max}=3,Y_{min}=-1,X_{scl}=2,Y_{scl}=1.$