## Precalculus (10th Edition)

Published by Pearson

# Appendix B - Graphing Utilities - B.1 The Viewing Rectangle - B.1 Exercises - Page B2: 10

#### Answer

$X_{max}=-10,X_{min}=-22,Y_{max}=8,Y_{min}=4,X_{scl}=2,Y_{scl}=1.$

#### Work Step by Step

As we can see on the figure: $X_{max}=-10,X_{min}=-22,Y_{max}=8,Y_{min}=4.$ There are $6$ sections on the "x-axis", hence $X_{scl}=\frac{X_{max}-X_{min}}{6}=\frac{-10-(-22)}{6}=2.$ There are $4$ sections on the "y-axis", hence $Y_{scl}=\frac{Y_{max}-Y_{min}}{4}=\frac{8-4}{4}=1.$ Thus $X_{max}=-10,X_{min}=-22,Y_{max}=8,Y_{min}=4,X_{scl}=2,Y_{scl}=1.$

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