Functions Modeling Change: A Preparation for Calculus, 5th Edition

Published by Wiley
ISBN 10: 1118583191
ISBN 13: 978-1-11858-319-7

Chapter 9 - Trigonometric Identities, Models, and Complex Numbers - 9.1 Trigonometric Equations - Exercises and Problems for Section 9.1 - Exercises and Problems - Page 357: 8

Answer

$$θ=\frac{\pi }{12}$$

Work Step by Step

Solving the equation using inverse trigonometric functions, we find: $$2\sqrt{3}\tan \left(2θ\right)+1=3,\:0\le \:θ\le \frac{\pi }{2} \\ \tan \left(2θ\right)=\frac{\sqrt{3}}{3} \\ θ=\frac{\pi }{12}+\frac{\pi n}{2} \\ θ=\frac{\pi }{12}$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.