Functions Modeling Change: A Preparation for Calculus, 5th Edition

Published by Wiley
ISBN 10: 1118583191
ISBN 13: 978-1-11858-319-7

Chapter 9 - Trigonometric Identities, Models, and Complex Numbers - 9.1 Trigonometric Equations - Exercises and Problems for Section 9.1 - Exercises and Problems - Page 357: 21


$$x=1.25 ,\:x=\pi +0.747 $$

Work Step by Step

Solving the equation using inverse trigonometric functions, we find: $$\sin \left(x-1\right)=0.25,\:0\le \:x\le \:2\pi \\ x=\arcsin \left(0.25\right)+2\pi n+1,\:x=\pi -\arcsin \left(0.25\right)+2\pi n+1 \\ x=1.25 ,\:x=\pi +0.747 $$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.