Chapter 9 - Trigonometric Identities, Models, and Complex Numbers - 9.1 Trigonometric Equations - Exercises and Problems for Section 9.1 - Exercises and Problems - Page 357: 21

$$x=1.25 ,\:x=\pi +0.747 $$

Solving the equation using inverse trigonometric functions, we find: $$\sin \left(x-1\right)=0.25,\:0\le \:x\le \:2\pi \\ x=\arcsin \left(0.25\right)+2\pi n+1,\:x=\pi -\arcsin \left(0.25\right)+2\pi n+1 \\ x=1.25 ,\:x=\pi +0.747 $$