Answer
$$θ=\frac{0.9272 }{3}, \frac{\pi -0.927}{3}$$
Work Step by Step
Solving the equation using inverse trigonometric functions, we find:
$$5\sin \left(3θ\right)=4,\:0\le \:θ\le \frac{\pi }{2} \\ \sin \left(3θ\right)=\frac{4}{5} \\ θ=\frac{0.9272 }{3}, \frac{\pi -0.927}{3}$$