## Functions Modeling Change: A Preparation for Calculus, 5th Edition

$$\left(3,\:-\sqrt{3}\right)$$
Converting the polar coordinates to Cartesian coordinates, we find: $$x=2\sqrt{3}\cos \left(-\frac{\pi }{6}\right)=3\\ y=2\sqrt{3}\sin \left(-\frac{\pi }{6}\right) =-\sqrt3 \\ \left(3,\:-\sqrt{3}\right)$$