Chapter 8 - Triangle Trigonometry and Polar Coordinates - 8.3 Polar Coordinates - Exercises and Problems for Section 8.3 - Exercises and Problems - Page 347: 14

$$\left(\sqrt{2},\:\frac{\pi }{4}\right)$$

Converting the Cartesian coordinates to polar coordinates, we find: $$r=\sqrt{1^2+1^2} \\ r=\sqrt{2} \\ AND\\ θ=\arctan \left(\frac{1}{1}\right) \\ θ=\frac{\pi }{4} \\ \text{Thus, it follows:} \\ \left(\sqrt{2},\:\frac{\pi }{4}\right)$$