Functions Modeling Change: A Preparation for Calculus, 5th Edition

Published by Wiley
ISBN 10: 1118583191
ISBN 13: 978-1-11858-319-7

Chapter 8 - Triangle Trigonometry and Polar Coordinates - 8.3 Polar Coordinates - Exercises and Problems for Section 8.3 - Exercises and Problems - Page 347: 20



Work Step by Step

Converting the polar coordinates to Cartesian coordinates, we find: $$x=\sqrt{3}\cos \left(\left(-\frac{3\pi }{4}\right)\right)= -\sqrt{\frac{3}{2}} \\ y=\sqrt{3}\sin \left(\left(-\frac{3\pi }{4}\right)\right) = -\sqrt{\frac{3}{2}} \\ \left(-\sqrt{\frac{3}{2}},\:-\sqrt{\frac{3}{2}}\right)$$
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