Functions Modeling Change: A Preparation for Calculus, 5th Edition

Published by Wiley
ISBN 10: 1118583191
ISBN 13: 978-1-11858-319-7

Chapter 7 - Trigonometry and Periodic Functions - 7.6 The Tangent Function - Exercises and Problems for Section 7.6 - Exercises and Problems - Page 303: 20

Answer

A horizontal push rightward of $\tan \theta$ by $\pi/2$ units.

Work Step by Step

Since the transformation $f(x)$ to $f(x-h)$ for a positive $h$ is a horizontal shift $h$ units, this $m(\theta)$ can be thought of as $f(\theta-\pi/2)$ for $f(\theta)=\tan \theta$.Therefore, this is a horizontal push rightward of $\tan \theta$ by $\pi/2$ units.
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