Answer
A horizontal push rightward of $\tan \theta$ by $\pi/2$ units.
Work Step by Step
Since the transformation $f(x)$ to $f(x-h)$ for a positive $h$ is a horizontal shift $h$ units, this $m(\theta)$ can be thought of as $f(\theta-\pi/2)$ for $f(\theta)=\tan \theta$.Therefore, this is a horizontal push rightward of $\tan \theta$ by $\pi/2$ units.