Answer
Vertical stretch of $\tan \theta$.
Work Step by Step
Since the transformation $f(x)$ to $kf(x)$ for $k \gt 1$ stretches the function vertically, this new function is a vertically stretched version of $\tan \theta$.
Functions Modeling Change: A Preparation for Calculus, 5th Edition
by Connally, Eric; Hughes-Hallett, Deborah; Gleason, Andrew M.; Cheifetz, Phil C.
Published by
Wiley
ISBN 10:
1118583191
ISBN 13:
978-1-11858-319-7
Chapter 7 - Trigonometry and Periodic Functions - 7.6 The Tangent Function - Exercises and Problems for Section 7.6 - Exercises and Problems - Page 303: 16
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