Functions Modeling Change: A Preparation for Calculus, 5th Edition

Published by Wiley
ISBN 10: 1118583191
ISBN 13: 978-1-11858-319-7

Chapter 7 - Trigonometry and Periodic Functions - 7.6 The Tangent Function - Exercises and Problems for Section 7.6 - Exercises and Problems - Page 303: 1

Answer

$\sin 0^\circ=0$ $\cos 0^\circ=1$ $\tan 0^\circ = 0$

Work Step by Step

Sin and cos values should be simpler to calculate using the unit circle. An angle of $0^\circ$ from the horizontal should give an $x$ value or cosine value of $\cos 0^\circ=1$ and a $y$ value or sine value of $\sin 0^\circ=0$. Since $\tan 0^\circ = \frac{\sin 0^\circ}{\cos 0^\circ}$, the expression becomes $$\tan 0^\circ = \frac{0}{1}=0$$
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