Answer
a) $
B=1200 e^{0.03(100)}=\$24,102.64
$
b) $t \approx 124.323$
Work Step by Step
(a) At the end of 100 years,
$$
B=1200 e^{0.03(100)}=\$24,102.64
$$
(b) Make a graph of both $B=1200 e^{0.03 t}$ and $B=50000$ and find $t \approx 124.323$ years.
