Answer
See the explanation
Work Step by Step
- All three investments begin at $t=0$ with a value of $\$ 1000$.
- Investment 1: $V=1000 e^{0.115 t}$ earns interest at a continuous annual rate of $11.5 \%$.
- Investment 2: $V=1000 \cdot 2^{t / 6}$ doubles in value every 6 years.
- Investment 3: $V=1000(1.122)^t$ grows by $12.2 \%$ every year.
