Functions Modeling Change: A Preparation for Calculus, 5th Edition

Published by Wiley
ISBN 10: 1118583191
ISBN 13: 978-1-11858-319-7

Chapter 4 - Exponential Functions - 4.5 The Number e - Exercises and Problems for Section 4.5 - Exercises and Problems - Page 173: 25

Answer

a) $271.83$ b) $28.40\%$ per hour

Work Step by Step

(a) Since the population of the bacteria is growing by a constant continuous percent rate, the function can be modelled as an exponential function, $a=100$ and $b=0.25$. $$ P=100 e^{0.25t} $$ The bacteria colony after 4 hours is $$ P=100 e^{0.25\cdot 4}= 271.83 $$ b) Rewrite the above function in the form: $P=a b^t$. $$ P(t)=100\left(e^{0.25}\right)^t \approx 100(1.2840)^t $$ From this, we see that $b=1.2840$. The population increases by about $28.40 \%$ per hour.
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