Answer
See the graph below.
Work Step by Step
As $x \rightarrow \infty$, we know that $3(0.9)^x \rightarrow 0$ because it exponentially decays to zero. Therefore, as $x \rightarrow \infty$, we have $f(x)= 5+3(0.9)^x \rightarrow 5+0=5$.
This function has a horizontal asymptote at 5.