Chapter 4 - Exponential Functions - 4.1 Introduction to the Family of Exponential Functions - Exercises and Problems for Section 4.1 - Exercises and Problems - Page 148: 63

$a_1>a_0$ and $\tau_1 > \tau_0 $.

Given: $f(t)=a_0\cdot2^{-t/\tau_0}$ $g(t)=a_1\cdot2^{-t/\tau_1}$ It is clear that $a_1>a_0$ because $a_1=g(0)>f(0)=a_0$ and $\tau_1 > \tau_0 $ because the graph of $f$ decays faster than that of $g$.