## Functions Modeling Change: A Preparation for Calculus, 5th Edition

Yes, $K(x)=\frac{1}{3}\left(\frac{2}{3}\right)^x$
Use the fact that $\left(\frac{a}{b}\right)^n=\frac{a^n}{b^n}$ to simplify the function to an exponential in the listed form. $$K(x)=\frac{1}{3}\left(\frac{2}{3}\right)^x$$