Answer
Yes, $g(w)=2\left(\frac{1}{2}\right)^w$
Work Step by Step
Since $a^{-b}=\frac{1}{a^b}$, this function is the same as $$g(w)=2\left(\frac{1}{2}\right)^w$$ Thus, the function is exponential with $a=2$ and $b=\frac{1}{2}$.
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