## Functions Modeling Change: A Preparation for Calculus, 5th Edition

Yes, $g(w)=2\left(\frac{1}{2}\right)^w$
Since $a^{-b}=\frac{1}{a^b}$, this function is the same as $$g(w)=2\left(\frac{1}{2}\right)^w$$ Thus, the function is exponential with $a=2$ and $b=\frac{1}{2}$.