## Functions Modeling Change: A Preparation for Calculus, 5th Edition

Yes, $m(t)=8 \cdot 27^t$
Since $(ab)^n=a^nb^n$, this function simplifies to $$m(t)=2^3 \cdot (3^t)^3$$ Using the fact that $(a^b)^c=a^{bc}$, $(3^t)^3=3^{3t}=(3^3)^t=27^t$. This leaves an exponential function of $$m(t)=8 \cdot 27^t$$