#### Answer

$$\frac{1-2\ln \left(x\right)}{3x^3}$$

#### Work Step by Step

Simplifying using the rules of fractions, we find:
$$\frac{\frac{1}{x}\cdot \:3x^2-\ln \left(x\right)\cdot \:6x}{\left(3x^2\right)^2} \\ \frac{3x-6x\ln \left(x\right)}{3^2x^4} \\ \frac{3x\left(1-2\ln \left(x\right)\right)}{3^2x^4} \\ \frac{1-2\ln \left(x\right)}{3x^3}$$