## Functions Modeling Change: A Preparation for Calculus, 5th Edition

$$\frac{b-1}{b^2}$$
Simplifying using the rules of fractions, we find: $$\frac{\frac{b^2-1}{b^2}}{b+1} \\ \frac{\left(b+1\right)\left(b-1\right)}{b^2\left(b+1\right)} \\ \frac{b-1}{b^2}$$