Functions Modeling Change: A Preparation for Calculus, 5th Edition

Published by Wiley
ISBN 10: 1118583191
ISBN 13: 978-1-11858-319-7

Chapter 11 - Polynomial and Rational Functions - Exercises to Skills Review for Chapter 11 - Page 494: 36

Answer

$$=\frac{p^3}{p^2+q^2}$$

Work Step by Step

Simplifying using the rules of fractions, we find: $$p-\frac{pq^2}{p^2+q^2} \\ -\frac{pq^2}{p^2+q^2}+\frac{p\left(p^2+q^2\right)}{p^2+q^2} \\ \frac{-pq^2+p\left(p^2+q^2\right)}{p^2+q^2} \\ =\frac{p^3}{p^2+q^2}$$
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