Functions Modeling Change: A Preparation for Calculus, 5th Edition

Published by Wiley
ISBN 10: 1118583191
ISBN 13: 978-1-11858-319-7

Chapter 11 - Polynomial and Rational Functions - 11.1 Power Functions and Proportionality - Exercises and Problems for Section 11.1 - Skill Refresher - Page 439: S2

Answer

$9x^5$

Work Step by Step

Use the fact that $\sqrt{a} \equiv a^\frac{1}{2}$, $$(3x(x^3)^\frac{1}{2})^2$$ Since $(a^m)^n=a^{mn}$, the expression becomes $$(3x(x^\frac{3}{2})^2$$ Finally, since $(ab)^n=a^nb^n$ and $a^m(a^n)=a^{m+n}$, the expression simplifies to $$3^2 \cdot x^2 \cdot x^{(3/2)(2)}=9x^2 \cdot x^3=9x^5$$
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