Functions Modeling Change: A Preparation for Calculus, 5th Edition

Published by Wiley
ISBN 10: 1118583191
ISBN 13: 978-1-11858-319-7

Chapter 11 - Polynomial and Rational Functions - 11.1 Power Functions and Proportionality - Exercises and Problems for Section 11.1 - Skill Refresher - Page 439: S1


$\pm 6t$

Work Step by Step

Since $\sqrt{ab}=\sqrt{a} \cdot \sqrt{b}$ for all positive $a,b$, $$\sqrt{36t^2}=\sqrt{36} \cdot \sqrt{t^2}=\pm 6t$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.