Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Test - Page 325: 36



Work Step by Step

$\frac{8}{25}$ + $\frac{7}{50}$ The LCD (least common denominator) is 50, so multiply $\frac{8}{25}$ by $\frac{2}{2}$: ($\frac{8}{25}$)($\frac{2}{2}$) = $\frac{16}{50}$ Now, solve the original equation: $\frac{16}{50}$ + $\frac{7}{50}$ = $\frac{23}{50}$
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