## Prealgebra (7th Edition)

$\frac{23}{50}$
$\frac{8}{25}$ + $\frac{7}{50}$ The LCD (least common denominator) is 50, so multiply $\frac{8}{25}$ by $\frac{2}{2}$: ($\frac{8}{25}$)($\frac{2}{2}$) = $\frac{16}{50}$ Now, solve the original equation: $\frac{16}{50}$ + $\frac{7}{50}$ = $\frac{23}{50}$