Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Test: 27



Work Step by Step

To find the average of a set of terms, add up all of the terms, then divide the sum by the number of terms in the set. The following are the calculations taken to find the average of $\frac{5}{6}$, $\frac{4}{3}$, and $\frac{7}{12}$. $(\frac{5}{6}+\frac{4}{3}+\frac{7}{12})\div3$ $=(\frac{10}{12}+\frac{16}{12}+\frac{7}{12})\div3$ $=(\frac{26}{12}+\frac{7}{12})\div3$ $=\frac{33}{12}\div3$ $=\frac{33}{12}\div\frac{3}{1}$ $=\frac{33}{12}\times\frac{1}{3}$ $=\frac{11}{12}\times\frac{1}{1}$ $=\frac{11}{12}$ The average of $\frac{5}{6}$, $\frac{4}{3}$, and $\frac{7}{12}$ is $\frac{11}{12}$.
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