Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Test: 28

Answer

$\frac{3}{4x}$

Work Step by Step

$\frac{\frac{5x}{7}}{\frac{20x^{2}}{21}}$ $=\frac{5x}{7}\div\frac{20x^{2}}{21}$ $=\frac{5x}{7}\times\frac{21}{20x^{2}}$ $=\frac{1}{1}\times\frac{3}{4x}$ $=\frac{3}{4x}$
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