Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Section 4.8 - Solving Equations Containing Fractions - Exercise Set - Page 311: 41



Work Step by Step

$\frac{3x}{10}$ + $\frac{x}{6}$ =$\frac{3x\times3}{10\times3}$ +$\frac{x\times5}{6\times5}$ LCD of 10 and 6 is 30 =$\frac{9x}{30}$ +$\frac{5x}{30}$ =$\frac{9x+5x}{30}$ =$\frac{14x}{30}$ =$\frac{2\times7x}{2\times15}$ =$\frac{7x}{15}$
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