Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Section 4.8 - Solving Equations Containing Fractions - Exercise Set - Page 311: 15



Work Step by Step

$\frac{7}{8}$ -$\frac{1}{8}$=$\frac{7-1}{8}$ =$\frac{6}{8}$ = $\frac{2\times3}{2\times4}$=$\frac{3}{4}$
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