## Prealgebra (7th Edition)

$\frac{6+7x}{3}$
2 + $\frac{7x}{3}$ =$\frac{2}{1}$ +$\frac{7x}{3}$ = $\frac{2\times3}{1\times3}$ +$\frac{7x}{3}$ LCD of 3 and 1 is 3 =$\frac{6}{3}$ +$\frac{7x}{3}$ =$\frac{6+7x}{3}$