#### Answer

$\frac{22^{}}{25y^{2}}$

#### Work Step by Step

$\frac{2}{5y}$$\div$$\frac{5y}{11}$= $\frac{2}{5y}$$\times$$\frac{11}{5y}$=
=$\frac{2\times11}{5y\times5y}$=
=$\frac{22^{}}{25y^{2}}$

Published by
Pearson

ISBN 10:
0321955048

ISBN 13:
978-0-32195-504-3

$\frac{22^{}}{25y^{2}}$

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