Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Section 4.3 - Multiplying and Dividing Fractions - Exercise Set: 21

Answer

$\frac{4}{9}$

Work Step by Step

$(-\frac{2}{3})^2=(-\frac{2}{3})\times(-\frac{2}{3})=\frac{2\times2}{3\times3}=\frac{4}{9}$
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