## Prealgebra (7th Edition)

Published by Pearson

# Chapter 4 - Section 4.3 - Multiplying and Dividing Fractions - Exercise Set - Page 247: 28

#### Answer

$\frac{1}{10}$

#### Work Step by Step

-$\frac{4}{15}$$\div -\frac{8}{3} = =-\frac{4}{15}$$\times$$-\frac{3}{8}$= The product of 2 negative numbers is a positive number. =$\frac{4\times3}{15\times8}$=$\frac{4\times3} {5\times3\times2\times4}$= =$\frac{1}{5\times2}$=$\frac{1}{10}$

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