Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 3 - Section 3.3 - Solving Linear Equations in One Variable - Exercise Set: 43

Answer

The solution is 3

Work Step by Step

-10(x+3) +28= -16 -16 Apply the distributive property -10$\times$x -10$\times$3 + 28 = -32 Multiply -10x -30 +28 = -32 Simplify -10x -2 =-32 Add 2 to both sides -10x -2+2 =-32 +2 -10x =-30 Divide by -10 both sides $\frac{-10x}{-10}$=$\frac{-30}{-10}$ x=3 The solution is 3 Check -10(x+3) +28= -16 -16 -10(3+3) +28= -16 -16 -10(6) +28=-32 -60 +28=-32 -32=-32
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