Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 3 - Section 3.3 - Solving Linear Equations in One Variable - Exercise Set - Page 189: 55


The solution is -5

Work Step by Step

7(y-2)=4y-29 Apply the distributive property 7y-14=4y-29 Add 14 to both sides 7y-14+14=4y-29 +14 7y=4y-15 Subtract 4y from both sides 7y-4y=4y-15 -4y Simplify 3y=-15 Divide by 3 on both sides $\frac{3y}{3}$=$\frac{-15}{3}$ y= -5 The solution is -5 Check 7(y-2)=4y-29 7(-5-2)=4(-5)-29 7(-7)=-20-29 -49=-49
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