Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 3 - Section 3.3 - Solving Linear Equations in One Variable - Exercise Set - Page 189: 33


The solution is 5

Work Step by Step

3r+4=19 Subtract 4 from both sides 3r+4 -4=19 -4 Simplify 3r =15 Divide by 3 on both sides $\frac{3r}{3}$ =$\frac{15}{3}$ r=5 The solution is 5 Check 3r+4=19 3$\times$5 +4=19 15+4=19 19=19
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