Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 3 - Section 3.3 - Solving Linear Equations in One Variable - Exercise Set: 18


The solution is 0

Work Step by Step

3(z+2)=5z+6 Apply the distributive property 3z+3$\times$ 2 =5z+6 3z+6=5z+6 Subtract -6 from both sides 3z+6-6=5z+6-6 3z= 5z Subtract 5z from both sides 3z-5z=5z-5z -2z=0 $\frac{-2z}{-2}$ =$\frac{0}{-2}$ z=0 The solution is 0 Check 3(z+2)=5z+6 3(0+2)=5$\times$0+6 3$\times$2=0+6 6=6
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