#### Answer

$40+4y-16=13y-12-3y$
$y=6$

#### Work Step by Step

Simplify and isolate the variables.
$13y-12-3y=40+4y-16$
Subtract 3y
$10y-12=40+4y-16$
Subtract 16.
$10y-12=4y+24$
Move terms
$6y-12=24$
Add 12
$6y=36$
Divide by 6
$y=6$

Published by
Pearson

ISBN 10:
0321955048

ISBN 13:
978-0-32195-504-3

$40+4y-16=13y-12-3y$
$y=6$

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