## Prealgebra (7th Edition)

$40+4y-16=13y-12-3y$ $y=6$
Simplify and isolate the variables. $13y-12-3y=40+4y-16$ Subtract 3y $10y-12=40+4y-16$ Subtract 16. $10y-12=4y+24$ Move terms $6y-12=24$ Add 12 $6y=36$ Divide by 6 $y=6$