Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 3 - Section 3.3 - Solving Linear Equations in One Variable - Exercise Set: 15

Answer

The solution is 5

Work Step by Step

3(x-1) -12 =0 3x-3$\times$ 1-12 =0 Apply the distributive property 3x-3 -12=0 Simplify 3x-15 =0 Add 15 to both sides 3x-15+15=0+15 3x=15 Divide both sides by 3 $\frac{3x}{3}$=$\frac{15}{3}$ x=5 The solution is 5 Check 3(x-1) -12 =0 3(5-1) -12 =0 Subtract inside the parentheses 3$\times$4 -12 =0 Multiply 12-12=0 0=0
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